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Embedded Phonics

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Embedded Phonics


Posted on : 2023-12-04 22:03:11 | Author : IGNOU Academy | View : 76

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Embedded Phonics is an instructional approach to teaching phonics within the context of meaningful reading and writing activities rather than as a separate, isolated skill. In the context of early years and foundational stage education, this method recognizes the importance of integrating phonics instruction _________ ___________ ____ _______ _____________ ____________ ____ ________ ____________ ______ ________ ____ ______ ____________ ___.
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Degree : PG DIPLOMA PROGRAMMES
Course Name : Post Graduate Diploma in Early Childhood and Foundational Stage Education
Course Code : PGDECFE
Subject Name : Curriculum and Pedagogy of Early Years and Foundational Stage Education: Part-2
Subject Code : MCD 3
Year : 2023



IGNOU MCD 3 Solved Assignment 2023
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Related Question


Considering the bytes 10001001 and 10101010 as elements of the field F2[X]/hg(X)i, where g(X) is the polynomial X 8 +X 4 +X 3 +X +1, find their product and quotient .


Process Skills


What do you understand by the term ‘Balance’ in the Balanced Comprehensive Approach to Literacy?


Decrypt the ciphertext 101000111001 which was encrypted with the Toy block cipher once using the key 101010010. Show all the steps.


One-to-One Correspondence


Another version of the columnar transposition cipher is the cipher using a key word. In this cipher, we encrypt as follows: Given a key word, we remove all the duplicate characters in the key word. For example, if the key word is ‘SECRET’, we remove the second ‘E’ and use ‘SECRT’ as the key word. To encrypt, we form a table as follows: In the first row, we write down the key word. In the following rows, we write the plaintext. Suppose we want to encrypt the text ‘ATTACKATDAWN’. We make a table as follows

Then we read off the columns in alphabetical order. We first read the column under ‘C’, followed by the columns under ‘E’, ‘R’, ‘S’ and ‘T’. We get the cipher text TTX TAN ADX AKW CAX. To decrypt, we reverse the process. Note that, since we know the length of the keyword, we can find the length of the columns by dividing the length of the message by the length of the keyword. Given the ciphertext ‘HNDWUEOESSRORUTXLARFASUXTINOOGFNEGASTORX’ and the key word ‘LANCE’, find the plaintext


Explain how Bob will decrypt the message.

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